Cointegrating equation: ln y t = β 0 + β 1 ln k t + β 2 ln h t + β 3 t + ln ϵ t P (Equation (33))

Null hypothesis

Model implication

LR test statistic

Critical value

Conclusion

(1) β 1 + β 2 = 1

α + β = 1

32.0027

χ 0.05 2 ( 1 ) = 3.84

Reject the null

(2) β 3 = 0

x = 0

39.5572

χ 0.05 2 ( 1 ) = 3.84

Reject the null

(3) β 1 + β 2 = 1 and β 3 = 0

α + β = 1 and x = 0

39.5771

χ 0.05 2 ( 2 ) = 5.99

Reject the null