h

$\tau$

$l^{\infty }$ -error

$l^2$ -error

$\frac{1}{2^5}$

$\frac{1}{2^5}$

0.0120

0.0037

$\frac{1}{2^6}$

$\frac{1}{2^6}$

6.7589e+13

1.3648e+13

$\frac{1}{2^7}$

$\frac{1}{2^7}$

1.7817e+44

4.0098e+43

$\frac{1}{2^8}$

$\frac{1}{2^8}$

9.6767e+104

1.7518e+104

$\frac{1}{2^9}$

$\frac{1}{2^9}$

1.6796e+227

inf