pi

i

Holm-Bonferroni

α H B = α / ( m + 1 i )

Holm-Sidak

α H S = 1 ( 1 α ) 1 / ( m + 1 i )

Benjamini-Hochberg

α B H = ( i / m ) × α

p1

1

0.05/6 = 0.0083

1 − (0.95)1/6 = 0.0085

(1/6) × 0.05 = 0.0083

p2

2

0.05/5 = 0.01

1 − (0.95)1/5 = 0.0102

(2/6) × 0.05 = 0.0167

p3

3

0.05/4 = 0.0125

1 − (0.95)1/4 = 0.0127

(3/6) × 0.05 = 0.025

p4

4

0.06/3 = 0.0167

1 − (0.95)1/3 = 0.0170

(4/6) × 0.05 = 0.0333

p5

5

0.05/2 = 0.025

1 − (0.95)1/2 = 0.0253

(5/6) × 0.05 = 0.0467

p6

6

0.05/1 = 0.05

1 − (0.95)1 = 0.05

(6/6) × 0.05 = 0.05