Collatz
Remer
n = 10/2 = 5
n = 5 × 3 = 15 + 1 = 16
n = 16/2 = 8
n = 8/2 = 4
n = 4/2 = 2
n = 2/1 = 1
n = 1
−3(−1) − 1 = 2
−3(−2) − 1 = 5
−3(−5) − 1 = 14
−3(−14) − 1 = 41
−3(−41) − 1 = 122
−3(−122) − 1 = 365
n = 365