Collatz

Remer

n = 10/2 = 5

n = 5 × 3 = 15 + 1 = 16

n = 16/2 = 8

n = 8/2 = 4

n = 4/2 = 2

n = 2/1 = 1

n = 1

−3(−1) − 1 = 2

−3(−2) − 1 = 5

−3(−5) − 1 = 14

−3(−14) − 1 = 41

−3(−41) − 1 = 122

−3(−122) − 1 = 365

n = 365