g 1 = 1 6 ( p V F + ( 1 p ) V B ) + λ b 2 a

g 2 = 1 2 ( p V F + ( 1 p ) V B )

g 3 = 0

g 4 = 1 24 ( p V F + ( 1 p ) V B ) + λ b 6 a

g 5 = 3 4 ( p V F + ( 1 p ) V B )