$\frac{2}{5}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^{\frac{5}{3}}\right)}^{\frac{3}{5}}}-\frac{1}{{\left[1-{\alpha }^{\frac{5}{3}}{\left(1-ϵ\right)}^{\frac{2}{3}}\right]}^{\frac{3}{5}}}$

$\frac{1}{2}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^2\right)}^{\frac{1}{2}}}-\frac{1}{{\left[1-{\alpha }^2\left(1-ϵ\right)\right]}^{\frac{1}{2}}}$

$\frac{3}{5}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^{\frac{5}{2}}\right)}^{\frac{2}{5}}}-\frac{1}{{\left[1-{\alpha }^{\frac{5}{2}}{\left(1-ϵ\right)}^{\frac{3}{2}}\right]}^{\frac{2}{5}}}$

$\frac{7}{10}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^{\frac{10}{3}}\right)}^{\frac{3}{10}}}-\frac{1}{{\left[1-{\alpha }^{\frac{10}{3}}{\left(1-ϵ\right)}^{\frac{7}{3}}\right]}^{\frac{3}{10}}}$

$\frac{3}{4}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^4\right)}^{\frac{1}{4}}}-\frac{1}{{\left[1-{\alpha }^4{\left(1-ϵ\right)}^3\right]}^{\frac{1}{4}}}$

$\frac{4}{5}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^5\right)}^{\frac{1}{5}}}-\frac{1}{{\left[1-{\alpha }^5{\left(1-ϵ\right)}^4\right]}^{\frac{1}{5}}}$

$\frac{8}{9}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^9\right)}^{\frac{1}{9}}}-\frac{1}{{\left[1-{\alpha }^9{\left(1-ϵ\right)}^8\right]}^{\frac{1}{9}}}$

$\frac{9}{10}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^{10}\right)}^{\frac{1}{10}}}-\frac{1}{{\left[1-{\alpha }^{10}{\left(1-ϵ\right)}^9\right]}^{\frac{1}{10}}}$

$\frac{95}{100}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^{20}\right)}^{\frac{5}{100}}}-\frac{1}{{\left[1-{\alpha }^{20}{\left(1-ϵ\right)}^{19}\right]}^{\frac{5}{100}}}$

$\frac{99}{100}$

${\text{Δ}}_{{\mathcal{R}}_{\alpha }}\left(1\right)=\frac{1}{{\left(1-{\alpha }^{100}\right)}^{\frac{1}{100}}}-\frac{1}{{\left[1-{\alpha }^{100}{\left(1-ϵ\right)}^{99}\right]}^{\frac{1}{100}}}$