Years of depositing/Years of calculation

Number of months necessary for degradation

-m-

Number of deposited months in

accordance with calendaristic years depositing(12n)

The equation of every calculus year -A_T after the first depositing year:

$\left(3+\left(8n\right)\right)t+7=\left(\left(12n\right)+13\right)-t$ , Equation(2)

1(2000)

0

$\left(12+1\right)$

$3t+7=13-t$ (Equation (1))

2(2001)1

9

$\left(\left(1\times 12\right)+13\right)$

$11t+7=25-t$ (Equation (2-1))

3(2002)2

7

$\left(\left(2\times 12\right)+13\right)$

$19t+7=37-t$ (Equation (2-2))

4(2003)3

14

$\left(\left(3\times 12\right)+13\right)$

$27t+7=49-t$ (Equation (2-3))

5(2004)4

13

$\left(\left(4\times 12\right)+13\right)$

$35t+7=61-t$ (Equation (2-4))

6(2005)5

12

$\left(\left(5\times 12\right)+13\right)$

$43t+7=73-t$ (Equation (2-5))

7(2006)6

11

$\left(\left(6\times 12\right)+13\right)$

$51t+7=85-t$ (Equation (2-6))

8(2007)7

9

$\left(\left(7\times 12\right)+13\right)$

$59t+7=97-t$ (Equation (2-7))

9(2008)8

13

$\left(\left(8\times 12\right)+13\right)$

$67t+7=109-t$ (Equation (2-8))

10 (2009)9

11

$\left(\left(9\times 12\right)+13\right)$

$75t+7=121-t$ (Equation (2-9))

11(2010)10

10

$\left(\left(10\times 12\right)+13\right)$

$83t+7=133-t$ (Equation (2-10))

12(2011)11

7

$\left(\left(11\times 12\right)+13\right)$

$91t+7=145-t$ (Equation (2-11))

13(2012)12

9

$\left(\left(12\times 12\right)+13\right)$

$99t+7=157-t$ (Equation (2-12))