For n = 3, we have | n(3,0): = R3(0) + (3) = 0 + 3 = 3 |
f3(S3,X3) = R3(X3) + (S3 − X3) | n(3,1): = R3(1) + (2) = 3 + 3 = 6 |
n(0,0): f3(0,0) = R3(0) + (0 − 0) | n(3,2): = R3(2) + (1) = 3 + 3 = 6 |
= R3(0) + (0) = 0 | n (3,3): = R3(3) + (0) = 2 + 0 = 2 |
n(1,0): f3(1, 0) = R3(0) + (1 − 0) | n(4,0): = R3(0) + (4) = 0 + 3 = 3 |
= R3 (0) + (1) = 0 + 3 = 3 | n(4,1): = R3(1) + (3) = 3 + 3 = 6 |
n(1,1): f3(1,1) = R3(1) + (0) = 3 + 0 = 3 | n(4,2): = R3(2) + (2) = 3 + 3 = 6 |
n(1,1): f3(1,1) = R3(1) + (0) = 3 + 0 = 3 | n(4,3): = R3(3) + (1) = 2+3 = 5 |
n (2,0): = R3(0) + (2) = 0 + 3 = 3 | n(4,4): = R3(4) + (0) = 3 + 0 = 3 |
n(2,1): = R3(1) + (1) = 3 + 3 = 6 | n(5,1): = R3(1) + (4) = 3 + 3 = 6 |
n(2,2): = R3(2) + (0) = 3 + 0 = 3 | n (5,2): = R3(2) + (3) = 3 + 3 = 6 |
n(5,0): = R3(0) + (5) = 0 + 3 = 3 | n(5,3): = R3(3) + (2) = 2 + 3 = 5 |
n(6,0): = R3(0) + (6) = 3 | n(5,4): = R3(4) + (1) = 3 + 3 = 6 |
n(6,1): = R3(1) + (5) = 6 | n(5,5): = R3(5) + (0) = 3 + 0 = 3 |
n(6,2): = R3(2) + (4) = 6 | |
n(6,3): = R3(3) + (3) = 5 | |
n(6,4): = R3(4) + (2) = 6 | |
n(6,5): = R3(5) + (1) = 6 | n (6,6): = R3(6) + (0) = 3 |