n(3,1) = R₂(1) + $f_3^{\ast }$ (2) = 3 + 6 = 9

n(6,1) = R₂(1) + $f_3^{\ast }$ (5) = 3 + 6 = 9

n(3,2) = R₂(2) + $f_3^{\ast }$ (1) = 3 + 3 = 6

n(6,2) = R₂(2) + $f_3^{\ast }$ (4) = 3 + 6 = 9

n(3,3) = R₂(3) + $f_3^{\ast }$ (0) = 3 + 0 = 3

n(6,3) = R₂(3) + $f_3^{\ast }$ (3) = 3 + 6 = 9

n (4, 0) = R₂(0) + $f_3^{\ast }$ (4) = 0 + 3 = 3

n (6, 4) = R₂(4) + $f_3^{\ast }$ (2) = 3 + 6 = 9

n (4, 2) = R₂(2) + $f_3^{\ast }$ (2) = 3 + 6 = 9

n (6, 5) = R₂(5) + $f_3^{\ast }$ (1) = 3 + 3 = 6

n (6, 6) = R₂(6) + $f_3^{\ast }$ (0) = 3 + 0 = 3