For n = 2, we have

n(4,3) = R2(3) + f 3 (1) = 3 + 3 = 6

f2(S2,X2) = R2(X0) + f 3 (S2 ? X2)

n(4,4) = R2(4) + f 3 (0) = 3 + 0 = 3

f2(0, 0) = R2(0) + f 3 (0) = 0

n(5,0) = R2(0) + f 3 (5) = 0 + 6 = 6

n(1,0) = R2(0) + f 3 (1) = 3

n(5,1) = R2(1) + f 3 (4) = 3 + 6 = 9

n(1,1) = R2(1) + f 3 (0) = 3

n(5,2) = R2(2) + f 3 (3) = 3 + 6 = 9

n(2,0) = R2(0) + f 3 (2) = 6

n(5,3) = R2(3) + f 3 (2) = 3 + 6 = 9

n(2,1) = R2(1) + f 3 (1) = 6

n(5,4) = R2(4) + f 3 (1) = 3 + 3 = 6

n(2,2) = R2(2) + f 3 (0) = 3

n(5,5) = R2(5) + f 3 (0) = 3 + 0 = 3

n(3,0) = R2(0) + f 3 (3) = 6

n(6,0) = R2(0) + f 3 (6) = 0 + 6 = 6