For n = 2, we have

n(4,3) = R₂(3) + $f_3^{\ast }$ (1) = 3 + 3 = 6

f₂(S₂,X₂) = R₂(X₀) + $f_3^{\ast }$ (S₂ ? X₂)

n(4,4) = R₂(4) + $f_3^{\ast }$ (0) = 3 + 0 = 3

f₂(0, 0) = R₂(0) + $f_3^{\ast }$ (0) = 0

n(5,0) = R₂(0) + $f_3^{\ast }$ (5) = 0 + 6 = 6

n(1,0) = R₂(0) + $f_3^{\ast }$ (1) = 3

n(5,1) = R₂(1) + $f_3^{\ast }$ (4) = 3 + 6 = 9

n(1,1) = R₂(1) + $f_3^{\ast }$ (0) = 3

n(5,2) = R₂(2) + $f_3^{\ast }$ (3) = 3 + 6 = 9

n(2,0) = R2(0) + $f_3^{\ast }$ (2) = 6

n(5,3) = R₂(3) + $f_3^{\ast }$ (2) = 3 + 6 = 9

n(2,1) = R₂(1) + $f_3^{\ast }$ (1) = 6

n(5,4) = R₂(4) + $f_3^{\ast }$ (1) = 3 + 3 = 6

n(2,2) = R₂(2) + $f_3^{\ast }$ (0) = 3

n(5,5) = R2(5) + $f_3^{\ast }$ (0) = 3 + 0 = 3

n(3,0) = R₂(0) + $f_3^{\ast }$ (3) = 6

n(6,0) = R₂(0) + $f_3^{\ast }$ (6) = 0 + 6 = 6