p

n

0

1

2

3

4

5

6

${\displaystyle {\sum }_{p\mathrm{<mo>\; =\; </mo>0}}^{n}F\left(n\mathrm{<mo>\; ;\; </mo>}p\right)}=\left|E\left(\mathcal{O}\mathcal{D}\mathcal{C}{\mathcal{P}}_n\right)\right|$

0

1

1

1

1

1

2

2

1

3

1

5

3

1

7

4

1

13

4

1

15

11

5

1

33

5

1

31

26

16

6

1

81

6

1

63

57

42

22

7

1

193