p

n

0

1

2

3

4

5

6

${\displaystyle {\sum }_{p\mathrm{<mo>\; =\; </mo>0}}^{n}F\left(n\mathrm{<mo>\; ;\; </mo>}p\right)}=\left|E\left(\mathcal{O}\mathcal{C}{\mathcal{P}}_n\right)\right|$

0

1

1

1

1

1

2

2

1

4

1

6

3

1

12

5

1

19

4

1

32

17

6

1

57

5

1

80

49

23

7

1

161

6

1

192

129

72

30

8

1

433