k

n

0

1

2

3

4

5

6

${\displaystyle {\sum }_{k\mathrm{<mo>\; =\; </mo>0}}^{n}F\left(n\mathrm{<mo>\; ;\; </mo>}k\right)}=\left|E\left(\mathcal{O}\mathcal{C}{\mathcal{P}}_n\right)\right|$

0

1

1

1

1

1

2

2

1

2

3

6

3

1

4

6

8

19

4

1

8

12

16

20

57

5

1

16

24

32

40

48

161

6

1

32

48

64

80

96

112

433