The change in the linear speed of the saw teeth depending on the change in the diameter of the saw blades, m/s

Change in peripheral speed in order to maintain linear speed, rpm

$v_{320}=\frac{\pi dn}{60}=\frac{3.14\times 0.32\times 730}{60}=12.2$

$n=\frac{60\cdot v_{320}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.32}=730$

$v_{310}=\frac{\pi dn}{60}=\frac{3.14\times 0.310\times 730}{60}=11.8$

$n=\frac{60\cdot v_{310}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.31}=752$

$v_{300}=\frac{\pi dn}{60}=\frac{3.14\times 0.3\times 730}{60}=11.5$

$n=\frac{60\cdot v_{300}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.3}=777$