Plots and curved Equations Equation No. Researcher (s) ○ Field Data [17] ◇ Field Data [15] □ Field Data [35] 1 ${E}_{m}=2RMR-100\text{\hspace{0.17em}}\text{for}\text{\hspace{0.17em}}RMR>50$ 3 [15] 2 ${E}_{\text{m}}={10}^{\left(RMR-10\right)/40}$ 4 [17] 3 ${E}_{m}={E}_{i}/100\left(0.0028RM{R}^{2}+0.9\mathrm{exp}\left(RMR/22.82\right)\right),{E}_{i}=50\text{Gpa}$ 5 [18] 4 ${E}_{m}={E}_{i}\left(0.5\left(1-\mathrm{cos}\left(\text{π}RMR/100\right)\right)\right),{E}_{i}=50\text{Gpa}$ 6 [19] 5 ${E}_{m}=0.1{\left(RMR/10\right)}^{3}$ 7 [20] 6 ${E}_{\text{m}}=10{Q}_{c}^{1/3}$ where ${Q}_{c}=Q{\sigma }_{ci}/100$ 8 [4] 7 ${E}_{m}=\left(1-\frac{d}{2}\right)\sqrt{\frac{{\sigma }_{ci}}{100}}×{10}^{\left(RMR-10\right)/40}$ 9 [38] 8 ${E}_{m}={E}_{i}{\left({S}^{a}\right)}^{0.4}{E}_{i}=50\text{GPa},s=\mathrm{exp}\left(\left(GSI-100\right)/9\right)$ 10 [24] 9 ${E}_{m}={E}_{i}{S}^{1/4}{E}_{i}=50\text{GPa},s=\mathrm{exp}\left(\left(GSI-100\right)/9\right)$ 11 [37] 10 ${E}_{m}=7\left(±3\right)\sqrt{{Q}^{\prime }}{Q}^{\prime }=10\left(\left(RMR-44\right)/21\right)$ 12 [36]