Day 1

Time hours

0

12

24

Energy balance

0

A + a − B − b = B + b

A + 2a − 2B − 3b = b

Temperature

T0

T1 + Δt

T0 + Δt

Day 2

Time hours

0

12

24

Energy balance

b

b + A + a − B − b = B + 2b

b + A + 2a − 2B − 3b = 2b

Temperature

T0+Δt

T1 + 2Δt

T0 + 2Δt