| Sample No | Ave Results (Y) | d | d2 | SD ( ) |
| 1 | 4 | −0.45 | 0.2025 |
SD = 0.11 2SD = 2 × 0.11 = 0.22 - OCV = SD/X × 100 = 2.2% Correlation coefficient r = 1 – 0.22/4.95 = 0.955 Test of significance at 0.05: using Pearson Moment correlation
Calculated value = 0 Critical value = 0.3687 Since 0.3687 > 0, Accept the hypothesis |
| 2 | 4 | −0.45 | 0.2025 | |
| 3 | 4 | −0.45 | 0.2025 | |
| 4 | 5 | 0.55 | 0.3025 | |
| 5 | 5 | 0.55 | 0.3025 | |
| 6 | 4 | −0.45 | 0.2025 | |
| 7 | 5 | 0.55 | 0.3025 | |
| 8 | 4 | −0.45 | 0.2025 | |
| 9 | 5 | 0.55 | 0.3025 | |
| 10 | 4 | −0.45 | 0.2025 | |
| 11 | 5 | 0.55 | 0.3025 | |
| 12 | 5 | 0.55 | 0.3025 | |
| 13 | 4 | −0.45 | 0.2025 | |
| 14 | 5 | 0.55 | 0.3025 | |
| 15 | 4 | −0.45 | 0.2025 | |
| 16 | 5 | 0.55 | 0.3025 | |
| 17 | 4 | −0.45 | 0.2025 | |
| 18 | 4 | −0.45 | 0.2025 | |
| 19 | 4 | −0.45 | 0.2025 | |
| 20 | 5 | 0.55 | 0.3025 | |
|
| ∑89 – X = 4.45 | ∑0 | ∑4.95 |