Sample

No

Ave Results

(Y)

d ( Y X ¯ )

d2 ( Y X ¯ ) 2

SD ( d 2 / n 1 )

1

4

−0.45

0.2025

d 2 / n 1 = 4.95 / 19 = 2.22 / 19

SD = 0.11

2SD = 2 × 0.11 = 0.22

-

OCV = SD/X × 100 = 2.2%

Correlation coefficient r = 1 – 0.22/4.95 = 0.955

Test of significance at 0.05: using Pearson Moment correlation

= d d 2 = 0 4.95 = 0

Calculated value = 0

Critical value = 0.3687

Since 0.3687 > 0, Accept the hypothesis

2

4

−0.45

0.2025

3

4

−0.45

0.2025

4

5

0.55

0.3025

5

5

0.55

0.3025

6

4

−0.45

0.2025

7

5

0.55

0.3025

8

4

−0.45

0.2025

9

5

0.55

0.3025

10

4

−0.45

0.2025

11

5

0.55

0.3025

12

5

0.55

0.3025

13

4

−0.45

0.2025

14

5

0.55

0.3025

15

4

−0.45

0.2025

16

5

0.55

0.3025

17

4

−0.45

0.2025

18

4

−0.45

0.2025

19

4

−0.45

0.2025

20

5

0.55

0.3025

∑89 – X = 4.45

∑0

∑4.95