Condition 1	Condition 2	Molecular counting
${e_{1} \notin E_{t 0 + 3}^{N} \| e_{1} \in E_{t 0}^{P}}$	$B_{t 0} (e_{1}) > B_{t 0} (e_{2})$	$s u m + 1$
	$B_{t 0} (e_{1}) < B_{t 0} (e_{2})$	$s u m + 0$
	$B_{t 0} (e_{1}) = B_{t 0} (e_{2})$	$s u m + 0.5$
${e_{1} \in E_{t 0 + 3}^{N} \| e_{1} \in E_{t 0}^{P}}$	$B_{t 0} (e_{1}) < B_{t 0} (e_{3})$	$s u m + 1$
	$B_{t 0} (e_{1}) > B_{t 0} (e_{3})$	$s u m + 0$
	$B_{t 0} (e_{1}) = B_{t 0} (e_{3})$	$s u m + 0.5$