Solution no 5 (pressure angle α = 20˚) Lower bound Lb = [as same as above] Upper bound Ub = [as same as above] Initial condition X0 = [as same as above] | ||||||
| 1st pinion | 2nd pinion | 3rd pinion | 4th pinion | Constant pinion | Rear pinion |
Module m | 3.4442 | 3.3699 | 3.2274 | 2.8270 | 3.6172 | 2.7136 |
Number of teeth z | 14.000 | 19.000 | 19.000 | 19.000 | 19.000 | 19.000 |
Helix angle β | 32.000 | 30.7584 | 30.7499 | 30.7265 | 30.7733 | 31.7088 |
Face width b | 34.000 | 33.000 | 32.000 | 32.000 | 32.000 | 44.000 |
Pressure angle αt | 23.2283 | 22.9551 | 22.9533 | 22.9483 | 22.9583 | 23.1628 |
Centre distance a | 80.000 | 79.9868 | 79.9857 | 79.9820 | 79.9885 | 79.9990 |
Transverse contact ratio εα | 1.4417 | 1.4672 | 1.4749 | 1.4955 | 1.4535 | 1.4930 |
Overlap ratio εβ | 1.6651 |
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Bending stress σF | 958.800 | 793.400 | 811.000 | 658.700 | 366.100 | 1000.700 |
Safety factor for bending stress SF | 1.0429 | 1.2604 | 1.2331 | 1.5182 | 2.7314 | 0.9993 |
Contact stress σH | 1025.100 | 870.300 | 811.600 | 783.800 | 610.700 | 1284.300 |
Safety factor for contact stress σH | 1.3658 | 1.6087 | 1.7249 | 1.7862 | 2.2926 | 1.0901 |