Solution no 4 (pressure angle α = 18˚) Lower bound Lb = [as same as above] Upper bound Ub = [as same as above] Initial condition X0 = [as same as above] | ||||||
| 1st pinion | 2nd pinion | 3rd pinion | 4th pinion | Constant pinion | Rear pinion |
Module m | 3.4442 | 3.3703 | 3.2278 | 2.8275 | 3.6175 | 2.7137 |
Number of teeth z | 14.000 | 19.000 | 19.000 | 19.000 | 19.000 | 19.000 |
Helix angle β | 32.000 | 30.7565 | 30.7478 | 30.7240 | 30.7716 | 31.7060 |
Face width b | 34.000 | 33.000 | 32.000 | 32.000 | 32.000 | 44.000 |
Pressure angle αt | 20.9637 | 20.7116 | 20.7099 | 20.7052 | 20.7146 | 20.9028 |
Centre distance a | 80.000 | 79.9942 | 79.9938 | 79.9922 | 79.9950 | 79.9996 |
Transverse contact ratio εα | 1.5077 | 1.5367 | 1.5459 | 1.5709 | 1.5202 | 1.5688 |
Overlap ratio εβ | 1.6651 |
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Bending stress σF | 927.6637 | 766.9720 | 783.5646 | 635.5152 | 354.2463 | 965.5743 |
Safety factor for bending stress SF | 1.0780 | 1.3038 | 1.2762 | 1.5735 | 2.8229 | 1.0357 |
Contact stress σH | 1000.240 | 850.300 | 792.700 | 764.600 | 597.100 | 1252.90 |
Safety factor for contact stress σH | 1.3967 | 1.6464 | 1.7661 | 1.8310 | 2.3448 | 1.1175 |