Solution no 2 (pressure angle α = 14˚) Lower bound Lb = [as same as above] Upper bound Ub = [as same as above] Initial condition X0 = [as same as above] | ||||||
| 1st pinion | 2nd pinion | 3rd pinion | 4th pinion | Constant pinion | Rear pinion |
Module m | 3.4442 | 3.3708 | 3.2282 | 2.8280 | 3.6179 | 2.7140 |
Number of teeth z | 14.000 | 19.000 | 19.000 | 19.000 | 19.000 | 19.000 |
Helix angle β | 32.000 | 30.7513 | 30.7423 | 30.7172 | 30.7671 | 31.6986 |
Face width b | 34.000 | 33.000 | 32.000 | 32.000 | 32.000 | 44.0000 |
Pressure angle αt | 16.3835 | 16.1785 | 16.1771 | 16.1731 | 16.1810 | 16.3329 |
Centre distance a | 80.000 | 80.000 | 80.000 | 80.000 | 80.000 | 80.000 |
Transverse contact ratio εα | 1.6768 | 1.7140 | 1.7277 | 1.7656 | 1.6901 | 1.7655 |
Overlap ratio εβ | 1.6651 |
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Bending stress σF | 858.9134 | 709.4125 | 723.8493 | 585.0816 | 328.3350 | 888.5450 |
Safety factor for bending stress SF | 1.1643 | 1.4096 | 1.3815 | 1.7092 | 3.0457 | 1.1254 |
Contact stress σH | 950.500 | 805.100 | 749.800 | 721.200 | 566.200 | 1181.000 |
Safety factor for contact stress σH | 1.4729 | 1.7389 | 1.8671 | 1.9412 | 2.4725 | 1.1854 |