Calculation various important features by strength limit number of earth

Parameters

Formulas

Equation No.

Thickness of homosphere

$TH=\left(e^{X_{C-\text{Earth}}}-1\right)\times 100=\frac{{\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}}{{10}^{11}}$

(82)

$TH=\frac{2g_0}{þ\times e^e\times {10}^8}=\frac{2g_0\times \text{A}\text{.D}}{þ\times {10}^8}$

(83)

$TH=\frac{2X_{C-\text{earth}}}{þ\times {10}^8}$

(84)

Distance value that light travel along one year

${\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}=\left(e^{X_{C-\text{Earth}}}-1\right)\times {10}^{13}$

(85)

${\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}^{\text{Now}}=\frac{1{\text{Pc}}_{\text{inkm}-\text{Now}}}{3.2}\times \left(e^{X_{C-\text{earth}}{}_{{}_{\text{Exact}}}}-1\right)$

(86)

${\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}^{\text{OLD}}=\frac{1{\text{Pc}}_{\text{inmiles}-\text{Old}}}{3.0739148433095432861689099115875\text{e}-6\text{millionlightyear}}\times \left(e^{X_{C-\text{earth}}{}_{{}_{\text{OLD}}}}-1\right)$

(87)

${\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}=TH\times {10}^{11}$

(88)

${\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}=\frac{2X_{C-\text{earth}}}{þ\times {10}^{-3}}$

(89)

${\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}=\frac{2g_0}{þ\times {10}^{-3}\times e^e}=\frac{2g_0\times \text{A}\text{.D}}{þ\times {10}^{-3}}$

(90)

1Parsec in Km

$1{\text{Pc}}_{\text{inkm}}=\frac{{\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}\times 3.2}{e^{X_{C-\text{Earth}}}-1}$

(91)

1Parsec in miles

$1{\text{Pc}}_{\text{inmiles}}=e^{X_{C-\text{Earth}}}\times {10}^{12}$

(92)

Equatorial radius

$R_{\text{EQUATOR}}=\left(\sec \left(X_{C-\text{Earth}}\right)-1\right)\times {10}^8$

(93)

Earth density

$E{D}_{\text{Now}}=X_{C-{\text{earth}}_{\text{OLD}}}^{0.56065834919309210862625764267195\times e}\times 10$

(94)

$E{D}_{\text{Old}}={\text{X}}_{C-{\text{earth}}_{\text{OLD}}}^{0.50298967401108908318025684564516\times e}\times 10$

(95)

$E{D}_{\text{Now}}=X_{C-{\text{earth}}_{\text{Exact}}}^{0.61559019634593296011795463607929\times e}\times 10$

(96)

$E{D}_{\text{Old}}=X_{C-{\text{earth}}_{\text{Exact}}}^{0.55227129432763323207435271052352\times e}\times 10$

(97)

$E{D}_{\text{Now}}=\frac{g_{0-\text{Old}}}{100X_{C-\text{earth}}{}_{{}_{\text{OLD}}}}+5=\frac{g_{0-\text{Old}}+500X_{C-\text{earth}}{}_{{}_{\text{OLD}}}}{100X_{C-\text{earth}}{}_{{}_{\text{OLD}}}}$

(98)

$E{D}_{\text{Now}}=\frac{1+500\text{A}\text{.D}}{100\text{A}\text{.D}}$

(99)

$E{D}_{\text{Now}}=\frac{g_{0-\text{Now}}}{100X_{C-\text{earth}}{}_{{}_{\text{Exact}}}}+5=\frac{g_{0-\text{Now}}+500X_{C-\text{earth}}{}_{{}_{\text{Exact}}}}{100X_{C-\text{earth}}{}_{{}_{\text{Exact}}}}$

(100)

Diameter of earth

$D_{\text{earth}}=\frac{10X_{C-\text{Earth}}}{\text{Volumepercentofheliumgasindryatmosphere}}$

(101)

Volume percent of helium gas in dry atmosphere

$V{P}_{\text{Heliumgas}-\text{dryatm}\text{.}}=\frac{10X_{C-\text{Earth}}}{D_{\text{earth}}}=\frac{10\times g_0\text{A}\text{.D}}{D_{\text{earth}}}$

(102)

Volume percent of xenon gas in dry atmosphere

$V{P}_{\text{Xenongas}-\text{dryatm}\text{.}}=\frac{X_{C-\text{Earth}}}{\text{orbitalinclinationtosun}’\text{sequator}\times {10}^4}$

(103)

Earth’s orbital inclination to sun’s equator

$O{I}_{\text{tosun}’\text{sequator}}=\frac{X_{C-\text{Earth}}}{V{P}_{\text{Xenongas-dryatm}\text{.}}\times {10}^4}$

(104)