Strength limit number of earth calculation formulas based on importance determinant features

Equations NO.

Determination of $X_{C-\text{Earth}}$ with thickness of homosphere

$X_{C-\text{Earth}}=\ln \left(\frac{\text{Thicknessofhomosphere}}{100}+1\right)=\ln \left(\frac{T{H}_{\text{homosphere}}}{100}+1\right)$

(63)

$X_{C-\text{Earth}}=\frac{\log \left(\frac{\text{Thicknessofhomosphere}}{100}+1\right)}{\log \left(e\right)}=\frac{\log \left(\frac{\text{Thicknessofhomosphere}}{100}+1\right)}{0.43429448190325182765112891891661}$

(64)

Determination of $X_{C-\text{Earth}}$ with distance that light travel along one year

$X_{C-\text{Earth}}=\ln \left[\left(\frac{\text{Distancethatlighttravelalongoneyear}}{{10}^{13}}\right)+1\right]=\ln \left[\left(\frac{{\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}}{{10}^{13}}\right)+1\right]$

(65)

$X_{C-\text{Earth}}=\frac{\log \left(\frac{{\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}}{{10}^{13}}+1\right)}{\log (e)}=\frac{\log \left(\frac{{\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}}{{10}^{13}}+1\right)}{0.43429448190325182765112891891661}$

(66)

Determination of $X_{C-\text{Earth}}$ with 1 Parsec value and ${\text{Distance}}_{\text{Light}⇝\text{1}\text{year}⇝\text{1}\text{year}}$

$X_{C-\text{earth}}{}_{{}_{\text{OLD}}}=\ln \left(\frac{{\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}^{\text{OLD}}\times 3.0739148433095432861689099115875}{1{\text{Pc}}_{\text{inkm}-\text{Old}}}+1\right)$

(67)

$X_{C-\text{earth}}{}_{{}_{\text{Exact}}}=\ln \left(\frac{{\text{Distance}}_{\text{Light}⇝\text{1}\text{year}}^{\text{Now}}\times 3.2}{1{\text{Pc}}_{\text{inkm}-\text{Now}}}+1\right)$

(68)

Determination of $X_{C-\text{Earth}}$ with 1 Parsec value in miles

$X_{C-\text{earth}}{}_{{}_{\text{OLD}}}=\ln \left(1.9100350099789003549065833483006\right)$

(69)

$X_{C-\text{earth}}{}_{{}_{\text{Exact}}}=\ln \left(1.9596150459074984227984337103851\right)$

$X_{C-\text{Earth}}=\ln \left(\frac{1\text{Parsecinmiles}}{{10}^{13}}\right)$

(70)

Determination of $X_{C-\text{Earth}}$ with a closest number to 1

$X_{C-\text{earth}}{}_{{}_{\text{OLD}}}={10}^{\frac{\log \left(0.99999999995244155209753649982147\right)}{{\left(X_{C-\text{earth}}{}_{{}_{\text{OLD}}}\right)}^{55}\times e}}$

(71)

Determination of $X_{C-\text{Earth}}$ with equatorial radius of earth

$X_{C-\text{Earth}}=\text{Arccos}\left[\frac{1}{\left(R_{\text{EQUATOR}}\times {10}^{-8}\right)+1}\right]$

(72)

Determination of $X_{C-\text{Earth}}$ with earth density

$X_{C-\text{earth}}{}_{{}_{\text{OLD}}}={\text{e}}^{\frac{\ln \frac{E{D}_{\text{Now}}}{10}}{0.56065834919309210862625764267195\times e}}={10}^{\frac{\log \frac{E{D}_{\text{Now}}}{10}}{0.56065834919309210862625764267195\times e}}$

(73)

$X_{C-\text{earth}}{}_{{}_{\text{OLD}}}=e^{\frac{\ln \frac{E{D}_{\text{Old}}}{10}}{0.50298967401108908318025684564516\times e}}={10}^{\frac{\log \frac{E{D}_{\text{Old}}}{10}}{0.50298967401108908318025684564516\times e}}$

(74)

$X_{C-\text{earth}}{}_{{}_{\text{Exact}}}=e^{\frac{\ln \frac{E{D}_{\text{Now}}}{10}}{0.61559019634593296011795463607929\times e}}={10}^{\frac{\log \frac{E{D}_{\text{Now}}}{10}}{0.61559019634593296011795463607929\times e}}$

(75)

$X_{C-\text{earth}}{}_{{}_{\text{Exact}}}=e^{\frac{\ln \frac{E{D}_{\text{Old}}}{10}}{0.55227129432763323207435271052352\times e}}={10}^{\frac{\log \frac{E{D}_{\text{Old}}}{10}}{0.55227129432763323207435271052352\times e}}$

(76)

$X_{C-\text{earth}}{}_{{}_{\text{OLD}}}=\frac{g_{0-\text{Old}}}{100\left(E{D}_{\text{Now}}-5\right)}$

(77)

$X_{C-e\text{arth}}{}_{{}_{\text{Exact}}}=\frac{g_{0-\text{Now}}}{100\left(E{D}_{\text{Now}}-5\right)}$

(78)

Determination of X_C-Earth with volume percent of helium gas in dry atmosphere

$X_{C-\text{Earth}}=1234.9648315313629613055429259477\times \text{Volumepercentofheliumgasindryatmosphere}$

(79)

$X_{C-\text{Earth}}=\left(V{P}_{\text{Heliumgas-dryatm}\text{.}}\times \frac{D_{\text{earth}}}{10}\right)$

(80)

Determination of X_C-Earth with xenon gas’s percent of volume in dry atmosphere

$X_{C-\text{Earth}}=\left(\text{Volumepercentofxenongasindryatmosphere}\times \text{orbitalinclinationtosun'sequator}\times {10}^4\right)$

(81)