Null Hypothesis

χ 2 Statistic

Critical Value

Conclusion

Δ ln k t does not Granger cause Δ ln y t

2.4176

χ 0.05 2 ( 1 ) = 3.84

Do not reject the null

Δ ln h t does not Granger cause Δ ln y t

3.6241

χ 0.05 2 ( 1 ) = 3.84

Do not reject the null

Δ ln k t and Δ ln h t do not Granger cause Δ ln y t

4.3135

χ 0.05 2 ( 2 ) = 5.99

Do not reject the null

Δ ln y t does not Granger cause Δ ln k t

15.3013

χ 0.05 2 ( 1 ) = 3.84

Reject the null

Δ ln h t does not Granger cause Δ ln k t

6.3031

χ 0.05 2 ( 1 ) = 3.84

Reject the null

Δ ln y t and Δ ln h t do not Granger cause Δ ln k t

15.3367

χ 0.05 2 ( 2 ) = 5.99

Reject the null

Δ ln y t does not Granger cause Δ ln h t

6.6776

χ 0.05 2 ( 1 ) = 3.84

Reject the null

Δ ln k t does not Granger cause Δ ln h t

2.5184

χ 0.05 2 ( 1 ) = 3.84

Do not reject the null

Δ ln y t and Δ ln k t do not Granger cause Δ ln h t

9.1806

χ 0.05 2 ( 2 ) = 5.99

Reject the null