CAN 2.0A

Maximum Length of the Frame for the Worst Case Scenario after Selective Bit Stuffing

CAN 2.0B

Maximum Length of the Frame for the Worst Case Scenario after Selective Bit Stuffing

Frame length = 114 + (max no of stuff bits) = 114 + 8 (with selective bit stuffing technique) = 122

Frame length = 131 + (max no of stuff bits) = 131 + 13 (with selective bit stuffing technique) = 144

Net bit rate = ((11 + 1 + 4 + 64)/122) * 1 Mbps = (80/122) * 1 Mbps = 655.73 kbps

Net bit rate = ((29 + 1 + 4 + 64)/144) * 1 Mbps = (98/144) * 1 Mbps = 680.55 kbps