The change in the linear speed of the saw teeth depending on the change in the diameter of the saw blades, m/s

Change in peripheral speed in order to maintain linear speed, rpm

$v_{320}=\frac{\pi dn}{60}=\frac{3.14\times 0.32\times 730}{60}=12.2$

$n=\frac{60\cdot v_{320}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.32}=730$

$v_{313}=\frac{\pi dn}{60}=\frac{3.14\times 0.313\times 730}{60}=12.0$

$n=\frac{60\cdot v_{313}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.313}=745$

$v_{306}=\frac{\pi dn}{60}=\frac{3.14\times 0.306\times 730}{60}=11.7$

$n=\frac{60\cdot v_{306}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.306}=762$

$v_{300}=\frac{\pi dn}{60}=\frac{3.14\times 0.3\times 730}{60}=11.5$

$n=\frac{60\cdot v_{300}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.3}=777$

$v_{294}=\frac{\pi dn}{60}=\frac{3.14\times 0.294\times 730}{60}=11.2$

$n=\frac{60\cdot v_{294}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.294}=793$

$v_{288}=\frac{\pi dn}{60}=\frac{3.14\times 0.288\times 730}{60}=11.0$

$n=\frac{60\cdot v_{288}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.288}=809$

$v_{282}=\frac{\pi dn}{60}=\frac{3.14\times 0.282\times 730}{60}=10.8$

$n=\frac{60\cdot v_{282}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.282}=827$

$v_{277}=\frac{\pi dn}{60}=\frac{3.14\times 0.277\times 730}{60}=10.6$

$n=\frac{60\cdot v_{277}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.277}=842$

$v_{272}=\frac{\pi dn}{60}=\frac{3.14\times 0.272\times 730}{60}=10.4$

$n=\frac{60\cdot v_{272}}{\pi d}=\frac{60\times 12.2}{3.14\times 0.272}=857$