Differential type
Tensor type
Condensed type
∇ ⋅ D = 4 π ρ
J ν = ∂ μ F μ ν
∂ λ ∂ σ ( ∂ λ Λ σ − ∂ σ Λ λ ) = 0
from
(4-2)
∇ × H = 4 π c J + 1 c ∂ D ∂ t
∇ × E = − 1 c ∂ B ∂ t
0 = ∂ λ F μ ν + ∂ μ F ν λ + ∂ ν F λ μ
∇ ⋅ B = 0
∇ ⋅ J + ∂ ρ ∂ t = 0
∂ λ J λ = 0