Integer exponent series

n

Exponent

v = (vf)(n)

vf = [(vf)(n)](1/n)

−3

−3

(100)(−3) = 10−6

(10−6)(−1/3) = 100

−2

−2

(100)(−2) = 10−4

(10−4)(−1/2) = 100

−1

−1

(100)(−1) = 10−2

(10−2)(−1/1) = 100

0

0

(100)(0) = 1

+1

+1

(100)(+1) = 10+2

(10+2)(+1/1) = 100

+2

+2

(100)(+2) = 10+4

(10+4)(+1/2) = 100

+3

+3

(100)(+3) = 10+6

(10+6)(+1/3) = 100