Sample No | Ave Results (Y) | d | d2 | SD ( ) |
1 | 4 | −0.45 | 0.2025 |
SD = 0.11 2SD = 2 × 0.11 = 0.22 - OCV = SD/X × 100 = 2.2% Correlation coefficient r = 1 – 0.22/4.95 = 0.955 Test of significance at 0.05: using Pearson Moment correlation
Calculated value = 0 Critical value = 0.3687 Since 0.3687 > 0, Accept the hypothesis |
2 | 4 | −0.45 | 0.2025 | |
3 | 4 | −0.45 | 0.2025 | |
4 | 5 | 0.55 | 0.3025 | |
5 | 5 | 0.55 | 0.3025 | |
6 | 4 | −0.45 | 0.2025 | |
7 | 5 | 0.55 | 0.3025 | |
8 | 4 | −0.45 | 0.2025 | |
9 | 5 | 0.55 | 0.3025 | |
10 | 4 | −0.45 | 0.2025 | |
11 | 5 | 0.55 | 0.3025 | |
12 | 5 | 0.55 | 0.3025 | |
13 | 4 | −0.45 | 0.2025 | |
14 | 5 | 0.55 | 0.3025 | |
15 | 4 | −0.45 | 0.2025 | |
16 | 5 | 0.55 | 0.3025 | |
17 | 4 | −0.45 | 0.2025 | |
18 | 4 | −0.45 | 0.2025 | |
19 | 4 | −0.45 | 0.2025 | |
20 | 5 | 0.55 | 0.3025 | |
| ∑89 – X = 4.45 | ∑0 | ∑4.95 |