Solution no 2 (pressure angle α = 14˚)

Lower bound Lb = [as same as above]

Upper bound Ub = [as same as above]

Initial condition X0 = [as same as above]

1st pinion

2nd pinion

3rd pinion

4th pinion

Constant pinion

Rear pinion

Module m

3.4442

3.3708

3.2282

2.8280

3.6179

2.7140

Number of teeth z

14.000

19.000

19.000

19.000

19.000

19.000

Helix angle β

32.000

30.7513

30.7423

30.7172

30.7671

31.6986

Face width b

34.000

33.000

32.000

32.000

32.000

44.0000

Pressure angle αt

16.3835

16.1785

16.1771

16.1731

16.1810

16.3329

Centre distance a

80.000

80.000

80.000

80.000

80.000

80.000

Transverse contact ratio εα

1.6768

1.7140

1.7277

1.7656

1.6901

1.7655

Overlap ratio εβ

1.6651

Bending stress σF

858.9134

709.4125

723.8493

585.0816

328.3350

888.5450

Safety factor for bending stress SF

1.1643

1.4096

1.3815

1.7092

3.0457

1.1254

Contact stress σH

950.500

805.100

749.800

721.200

566.200

1181.000

Safety factor for contact stress σH

1.4729

1.7389

1.8671

1.9412

2.4725

1.1854