$\text{CasimirRadiation}=C_{\text{Cas}}h\frac{\left(R_{\text{Earth}}{\omega }_{\text{Earth}}^2\cos {\theta }_{\text{lat}}\right)T_{\text{Earth}}^3}{{\left(\frac{r_{\text{tgt}}}{R_{\text{Earth}}}\right)}^2}$

Equation form found to match the measured ratio of Sun and Earth radiation

(14)

$C_{\text{Cas}}=\frac{\frac{{\omega }_{\text{Earth}}{R}_{\text{Earth}}}{c}}{R_{\text{Earth}}{\omega }_{\text{Earth}}^2\cos {\theta }_{\text{lat}}{T}_{\text{Earth}}^3}=2.259\times {10}^{-12}\left[\frac{{\text{s}}^{\text{2}}}{{\text{K}}^{\text{3}}\cdot \text{m}}\right]$

Solve for coefficient using the very accurate NASA data

(15)

$\frac{\Delta h_{\text{radial}}}{h}=C_{\text{Cas}}\frac{R{\omega }^2{T}^3}{{\left(\frac{r}{R}\right)}^2}\cos \theta$

Final formula for all Casimir radiation

(16)

$\frac{\Delta h_{\text{radial\_Earth}}}{h}=1.547\times {10}^{-6}$ from formula

$\text{EarthRadiation}=1.547\times {10}^{-6}$

measured

Cross-checks on final equation

$\frac{\Delta h_{\text{radial\_SUN}}}{h}=2.677\times {10}^{-3}$ from formula

$\text{SUNRadiation}=2.616\times {10}^{-3}$

measured